.02x^2-150x+10000=0

Solution for .02x^2-150x+10000=0 equation:

.02x^2-150x+10000=0

a = .02; b = -150; c = +10000;
Δ = b2-4ac
Δ = -1502-4·.02·10000
Δ = 21700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{21700}=\sqrt{100*217}=\sqrt{100}*\sqrt{217}=10\sqrt{217}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-10\sqrt{217}}{2*.02}=\frac{150-10\sqrt{217}}{0.04}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+10\sqrt{217}}{2*.02}=\frac{150+10\sqrt{217}}{0.04}
$